8(x+1)+3(2x-3)=41

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Solution for 8(x+1)+3(2x-3)=41 equation:


Simplifying
8(x + 1) + 3(2x + -3) = 41

Reorder the terms:
8(1 + x) + 3(2x + -3) = 41
(1 * 8 + x * 8) + 3(2x + -3) = 41
(8 + 8x) + 3(2x + -3) = 41

Reorder the terms:
8 + 8x + 3(-3 + 2x) = 41
8 + 8x + (-3 * 3 + 2x * 3) = 41
8 + 8x + (-9 + 6x) = 41

Reorder the terms:
8 + -9 + 8x + 6x = 41

Combine like terms: 8 + -9 = -1
-1 + 8x + 6x = 41

Combine like terms: 8x + 6x = 14x
-1 + 14x = 41

Solving
-1 + 14x = 41

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 14x = 41 + 1

Combine like terms: -1 + 1 = 0
0 + 14x = 41 + 1
14x = 41 + 1

Combine like terms: 41 + 1 = 42
14x = 42

Divide each side by '14'.
x = 3

Simplifying
x = 3

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