8(x+1)+3=2x+6(1+x)

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Solution for 8(x+1)+3=2x+6(1+x) equation: 



8(x+1)+3=2x+6(1+x)

We move all terms to the left:

8(x+1)+3-(2x+6(1+x))=0

We add all the numbers together, and all the variables

8(x+1)-(2x+6(x+1))+3=0

We multiply parentheses

8x-(2x+6(x+1))+8+3=0



We calculate terms in parentheses: -(2x+6(x+1)), so:

2x+6(x+1)

We multiply parentheses

2x+6x+6

We add all the numbers together, and all the variables

8x+6

Back to the equation:

-(8x+6)



We add all the numbers together, and all the variables

8x-(8x+6)+11=0

We get rid of parentheses

8x-8x-6+11=0

We add all the numbers together, and all the variables

5!=0

There is no solution for this equation

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