8(x+1)+4=-10(x-2)-7

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Solution for 8(x+1)+4=-10(x-2)-7 equation: 



8(x+1)+4=-10(x-2)-7

We move all terms to the left:

8(x+1)+4-(-10(x-2)-7)=0

We multiply parentheses

8x-(-10(x-2)-7)+8+4=0



We calculate terms in parentheses: -(-10(x-2)-7), so:

-10(x-2)-7

We multiply parentheses

-10x+20-7

We add all the numbers together, and all the variables

-10x+13

Back to the equation:

-(-10x+13)



We add all the numbers together, and all the variables

8x-(-10x+13)+12=0

We get rid of parentheses

8x+10x-13+12=0

We add all the numbers together, and all the variables

18x-1=0

We move all terms containing x to the left, all other terms to the right

18x=1

x=1/18

x=1/18

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