8(x+1)+4=3(2x-8)+16

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Solution for 8(x+1)+4=3(2x-8)+16 equation: 



8(x+1)+4=3(2x-8)+16

We move all terms to the left:

8(x+1)+4-(3(2x-8)+16)=0

We multiply parentheses

8x-(3(2x-8)+16)+8+4=0



We calculate terms in parentheses: -(3(2x-8)+16), so:

3(2x-8)+16

We multiply parentheses

6x-24+16

We add all the numbers together, and all the variables

6x-8

Back to the equation:

-(6x-8)



We add all the numbers together, and all the variables

8x-(6x-8)+12=0

We get rid of parentheses

8x-6x+8+12=0

We add all the numbers together, and all the variables

2x+20=0

We move all terms containing x to the left, all other terms to the right

2x=-20

x=-20/2

x=-10

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