8(x+1)-3(x+3)=4(x+3)-30

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Solution for 8(x+1)-3(x+3)=4(x+3)-30 equation: 



8(x+1)-3(x+3)=4(x+3)-30

We move all terms to the left:

8(x+1)-3(x+3)-(4(x+3)-30)=0

We multiply parentheses

8x-3x-(4(x+3)-30)+8-9=0



We calculate terms in parentheses: -(4(x+3)-30), so:

4(x+3)-30

We multiply parentheses

4x+12-30

We add all the numbers together, and all the variables

4x-18

Back to the equation:

-(4x-18)



We add all the numbers together, and all the variables

5x-(4x-18)-1=0

We get rid of parentheses

5x-4x+18-1=0

We add all the numbers together, and all the variables

x+17=0

We move all terms containing x to the left, all other terms to the right

x=-17

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