8(x+1)-4(x-3)-x=2

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Solution for 8(x+1)-4(x-3)-x=2 equation:


Simplifying
8(x + 1) + -4(x + -3) + -1x = 2

Reorder the terms:
8(1 + x) + -4(x + -3) + -1x = 2
(1 * 8 + x * 8) + -4(x + -3) + -1x = 2
(8 + 8x) + -4(x + -3) + -1x = 2

Reorder the terms:
8 + 8x + -4(-3 + x) + -1x = 2
8 + 8x + (-3 * -4 + x * -4) + -1x = 2
8 + 8x + (12 + -4x) + -1x = 2

Reorder the terms:
8 + 12 + 8x + -4x + -1x = 2

Combine like terms: 8 + 12 = 20
20 + 8x + -4x + -1x = 2

Combine like terms: 8x + -4x = 4x
20 + 4x + -1x = 2

Combine like terms: 4x + -1x = 3x
20 + 3x = 2

Solving
20 + 3x = 2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-20' to each side of the equation.
20 + -20 + 3x = 2 + -20

Combine like terms: 20 + -20 = 0
0 + 3x = 2 + -20
3x = 2 + -20

Combine like terms: 2 + -20 = -18
3x = -18

Divide each side by '3'.
x = -6

Simplifying
x = -6

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