8(x+1)-4x-2=(x-14)+(x+16)

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Solution for 8(x+1)-4x-2=(x-14)+(x+16) equation: 



8(x+1)-4x-2=(x-14)+(x+16)

We move all terms to the left:

8(x+1)-4x-2-((x-14)+(x+16))=0

We add all the numbers together, and all the variables

-4x+8(x+1)-((x-14)+(x+16))-2=0

We multiply parentheses

-4x+8x-((x-14)+(x+16))+8-2=0



We calculate terms in parentheses: -((x-14)+(x+16)), so:

(x-14)+(x+16)

We get rid of parentheses

x+x-14+16

We add all the numbers together, and all the variables

2x+2

Back to the equation:

-(2x+2)



We add all the numbers together, and all the variables

4x-(2x+2)+6=0

We get rid of parentheses

4x-2x-2+6=0

We add all the numbers together, and all the variables

2x+4=0

We move all terms containing x to the left, all other terms to the right

2x=-4

x=-4/2

x=-2

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