8(x+1)-5(x-3)=4(3x+1)+10

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Solution for 8(x+1)-5(x-3)=4(3x+1)+10 equation: 



8(x+1)-5(x-3)=4(3x+1)+10

We move all terms to the left:

8(x+1)-5(x-3)-(4(3x+1)+10)=0

We multiply parentheses

8x-5x-(4(3x+1)+10)+8+15=0



We calculate terms in parentheses: -(4(3x+1)+10), so:

4(3x+1)+10

We multiply parentheses

12x+4+10

We add all the numbers together, and all the variables

12x+14

Back to the equation:

-(12x+14)



We add all the numbers together, and all the variables

3x-(12x+14)+23=0

We get rid of parentheses

3x-12x-14+23=0

We add all the numbers together, and all the variables

-9x+9=0

We move all terms containing x to the left, all other terms to the right

-9x=-9

x=-9/-9

x=1

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