8(x+1)-5(x-3)=4(3x+1)+10

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Solution for 8(x+1)-5(x-3)=4(3x+1)+10 equation:



8(x+1)-5(x-3)=4(3x+1)+10
We move all terms to the left:
8(x+1)-5(x-3)-(4(3x+1)+10)=0
We multiply parentheses
8x-5x-(4(3x+1)+10)+8+15=0
We calculate terms in parentheses: -(4(3x+1)+10), so:
4(3x+1)+10
We multiply parentheses
12x+4+10
We add all the numbers together, and all the variables
12x+14
Back to the equation:
-(12x+14)
We add all the numbers together, and all the variables
3x-(12x+14)+23=0
We get rid of parentheses
3x-12x-14+23=0
We add all the numbers together, and all the variables
-9x+9=0
We move all terms containing x to the left, all other terms to the right
-9x=-9
x=-9/-9
x=1

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