8(x+1)-5=3(2x-4)-1

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Solution for 8(x+1)-5=3(2x-4)-1 equation: 



8(x+1)-5=3(2x-4)-1

We move all terms to the left:

8(x+1)-5-(3(2x-4)-1)=0

We multiply parentheses

8x-(3(2x-4)-1)+8-5=0



We calculate terms in parentheses: -(3(2x-4)-1), so:

3(2x-4)-1

We multiply parentheses

6x-12-1

We add all the numbers together, and all the variables

6x-13

Back to the equation:

-(6x-13)



We add all the numbers together, and all the variables

8x-(6x-13)+3=0

We get rid of parentheses

8x-6x+13+3=0

We add all the numbers together, and all the variables

2x+16=0

We move all terms containing x to the left, all other terms to the right

2x=-16

x=-16/2

x=-8

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