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8(x+1)=2(2x-2)
We move all terms to the left:
8(x+1)-(2(2x-2))=0
We multiply parentheses
8x-(2(2x-2))+8=0
We calculate terms in parentheses: -(2(2x-2)), so:We get rid of parentheses
2(2x-2)
We multiply parentheses
4x-4
Back to the equation:
-(4x-4)
8x-4x+4+8=0
We add all the numbers together, and all the variables
4x+12=0
We move all terms containing x to the left, all other terms to the right
4x=-12
x=-12/4
x=-3
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