8(x+1)=2(2x-2)

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Solution for 8(x+1)=2(2x-2) equation: 



8(x+1)=2(2x-2)

We move all terms to the left:

8(x+1)-(2(2x-2))=0

We multiply parentheses

8x-(2(2x-2))+8=0



We calculate terms in parentheses: -(2(2x-2)), so:

2(2x-2)

We multiply parentheses

4x-4

Back to the equation:

-(4x-4)



We get rid of parentheses

8x-4x+4+8=0

We add all the numbers together, and all the variables

4x+12=0

We move all terms containing x to the left, all other terms to the right

4x=-12

x=-12/4

x=-3

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