8(x+1)=2(4x-5)

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Solution for 8(x+1)=2(4x-5) equation:


Simplifying
8(x + 1) = 2(4x + -5)

Reorder the terms:
8(1 + x) = 2(4x + -5)
(1 * 8 + x * 8) = 2(4x + -5)
(8 + 8x) = 2(4x + -5)

Reorder the terms:
8 + 8x = 2(-5 + 4x)
8 + 8x = (-5 * 2 + 4x * 2)
8 + 8x = (-10 + 8x)

Add '-8x' to each side of the equation.
8 + 8x + -8x = -10 + 8x + -8x

Combine like terms: 8x + -8x = 0
8 + 0 = -10 + 8x + -8x
8 = -10 + 8x + -8x

Combine like terms: 8x + -8x = 0
8 = -10 + 0
8 = -10

Solving
8 = -10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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