8(x+1)=4(2x+3)

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Solution for 8(x+1)=4(2x+3) equation: 



8(x+1)=4(2x+3)

We move all terms to the left:

8(x+1)-(4(2x+3))=0

We multiply parentheses

8x-(4(2x+3))+8=0



We calculate terms in parentheses: -(4(2x+3)), so:

4(2x+3)

We multiply parentheses

8x+12

Back to the equation:

-(8x+12)



We get rid of parentheses

8x-8x-12+8=0

We add all the numbers together, and all the variables

-4!=0

There is no solution for this equation

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