8(x+1)=4(2x+3)

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Solution for 8(x+1)=4(2x+3) equation:



8(x+1)=4(2x+3)
We move all terms to the left:
8(x+1)-(4(2x+3))=0
We multiply parentheses
8x-(4(2x+3))+8=0
We calculate terms in parentheses: -(4(2x+3)), so:
4(2x+3)
We multiply parentheses
8x+12
Back to the equation:
-(8x+12)
We get rid of parentheses
8x-8x-12+8=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation

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