8(x+1)=4(2x+9)-28

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Solution for 8(x+1)=4(2x+9)-28 equation:


Simplifying
8(x + 1) = 4(2x + 9) + -28

Reorder the terms:
8(1 + x) = 4(2x + 9) + -28
(1 * 8 + x * 8) = 4(2x + 9) + -28
(8 + 8x) = 4(2x + 9) + -28

Reorder the terms:
8 + 8x = 4(9 + 2x) + -28
8 + 8x = (9 * 4 + 2x * 4) + -28
8 + 8x = (36 + 8x) + -28

Reorder the terms:
8 + 8x = 36 + -28 + 8x

Combine like terms: 36 + -28 = 8
8 + 8x = 8 + 8x

Add '-8' to each side of the equation.
8 + -8 + 8x = 8 + -8 + 8x

Combine like terms: 8 + -8 = 0
0 + 8x = 8 + -8 + 8x
8x = 8 + -8 + 8x

Combine like terms: 8 + -8 = 0
8x = 0 + 8x
8x = 8x

Add '-8x' to each side of the equation.
8x + -8x = 8x + -8x

Combine like terms: 8x + -8x = 0
0 = 8x + -8x

Combine like terms: 8x + -8x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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