8(x+1)=4(3x+2)

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Solution for 8(x+1)=4(3x+2) equation: 



8(x+1)=4(3x+2)

We move all terms to the left:

8(x+1)-(4(3x+2))=0

We multiply parentheses

8x-(4(3x+2))+8=0



We calculate terms in parentheses: -(4(3x+2)), so:

4(3x+2)

We multiply parentheses

12x+8

Back to the equation:

-(12x+8)



We get rid of parentheses

8x-12x-8+8=0

We add all the numbers together, and all the variables

-4x=0

x=0/-4

x=0

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