8(x+1)=6(3x-1)

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Solution for 8(x+1)=6(3x-1) equation: 



8(x+1)=6(3x-1)

We move all terms to the left:

8(x+1)-(6(3x-1))=0

We multiply parentheses

8x-(6(3x-1))+8=0



We calculate terms in parentheses: -(6(3x-1)), so:

6(3x-1)

We multiply parentheses

18x-6

Back to the equation:

-(18x-6)



We get rid of parentheses

8x-18x+6+8=0

We add all the numbers together, and all the variables

-10x+14=0

We move all terms containing x to the left, all other terms to the right

-10x=-14

x=-14/-10

x=1+2/5

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