8(x+10)+21x=12(x+5)-(16+x)

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Solution for 8(x+10)+21x=12(x+5)-(16+x) equation:



8(x+10)+21x=12(x+5)-(16+x)
We move all terms to the left:
8(x+10)+21x-(12(x+5)-(16+x))=0
We add all the numbers together, and all the variables
8(x+10)+21x-(12(x+5)-(x+16))=0
We add all the numbers together, and all the variables
21x+8(x+10)-(12(x+5)-(x+16))=0
We multiply parentheses
21x+8x-(12(x+5)-(x+16))+80=0
We calculate terms in parentheses: -(12(x+5)-(x+16)), so:
12(x+5)-(x+16)
We multiply parentheses
12x-(x+16)+60
We get rid of parentheses
12x-x-16+60
We add all the numbers together, and all the variables
11x+44
Back to the equation:
-(11x+44)
We add all the numbers together, and all the variables
29x-(11x+44)+80=0
We get rid of parentheses
29x-11x-44+80=0
We add all the numbers together, and all the variables
18x+36=0
We move all terms containing x to the left, all other terms to the right
18x=-36
x=-36/18
x=-2

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