8(x+10)+3=-6(x-5)-5

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Solution for 8(x+10)+3=-6(x-5)-5 equation: 



8(x+10)+3=-6(x-5)-5

We move all terms to the left:

8(x+10)+3-(-6(x-5)-5)=0

We multiply parentheses

8x-(-6(x-5)-5)+80+3=0



We calculate terms in parentheses: -(-6(x-5)-5), so:

-6(x-5)-5

We multiply parentheses

-6x+30-5

We add all the numbers together, and all the variables

-6x+25

Back to the equation:

-(-6x+25)



We add all the numbers together, and all the variables

8x-(-6x+25)+83=0

We get rid of parentheses

8x+6x-25+83=0

We add all the numbers together, and all the variables

14x+58=0

We move all terms containing x to the left, all other terms to the right

14x=-58

x=-58/14

x=-4+1/7

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