8(x+12)=10(x-2)

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Solution for 8(x+12)=10(x-2) equation: 



8(x+12)=10(x-2)

We move all terms to the left:

8(x+12)-(10(x-2))=0

We multiply parentheses

8x-(10(x-2))+96=0



We calculate terms in parentheses: -(10(x-2)), so:

10(x-2)

We multiply parentheses

10x-20

Back to the equation:

-(10x-20)



We get rid of parentheses

8x-10x+20+96=0

We add all the numbers together, and all the variables

-2x+116=0

We move all terms containing x to the left, all other terms to the right

-2x=-116

x=-116/-2

x=+58

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