8(x+2)+2(x-3)=7(x-3)

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Solution for 8(x+2)+2(x-3)=7(x-3) equation: 



8(x+2)+2(x-3)=7(x-3)

We move all terms to the left:

8(x+2)+2(x-3)-(7(x-3))=0

We multiply parentheses

8x+2x-(7(x-3))+16-6=0



We calculate terms in parentheses: -(7(x-3)), so:

7(x-3)

We multiply parentheses

7x-21

Back to the equation:

-(7x-21)



We add all the numbers together, and all the variables

10x-(7x-21)+10=0

We get rid of parentheses

10x-7x+21+10=0

We add all the numbers together, and all the variables

3x+31=0

We move all terms containing x to the left, all other terms to the right

3x=-31

x=-31/3

x=-10+1/3

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