8(x+2)-2(x-14)=-(6x-5)+2(x-6)

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Solution for 8(x+2)-2(x-14)=-(6x-5)+2(x-6) equation: 



8(x+2)-2(x-14)=-(6x-5)+2(x-6)

We move all terms to the left:

8(x+2)-2(x-14)-(-(6x-5)+2(x-6))=0

We multiply parentheses

8x-2x-(-(6x-5)+2(x-6))+16+28=0



We calculate terms in parentheses: -(-(6x-5)+2(x-6)), so:

-(6x-5)+2(x-6)

We multiply parentheses

-(6x-5)+2x-12

We get rid of parentheses

-6x+2x+5-12

We add all the numbers together, and all the variables

-4x-7

Back to the equation:

-(-4x-7)



We add all the numbers together, and all the variables

6x-(-4x-7)+44=0

We get rid of parentheses

6x+4x+7+44=0

We add all the numbers together, and all the variables

10x+51=0

We move all terms containing x to the left, all other terms to the right

10x=-51

x=-51/10

x=-5+1/10

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