8(x+2)-3(2x+1)=2(x+5)

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Solution for 8(x+2)-3(2x+1)=2(x+5) equation: 


Simplifying
8(x + 2) + -3(2x + 1) = 2(x + 5)

Reorder the terms:
8(2 + x) + -3(2x + 1) = 2(x + 5)
(2 * 8 + x * 8) + -3(2x + 1) = 2(x + 5)
(16 + 8x) + -3(2x + 1) = 2(x + 5)

Reorder the terms:
16 + 8x + -3(1 + 2x) = 2(x + 5)
16 + 8x + (1 * -3 + 2x * -3) = 2(x + 5)
16 + 8x + (-3 + -6x) = 2(x + 5)

Reorder the terms:
16 + -3 + 8x + -6x = 2(x + 5)

Combine like terms: 16 + -3 = 13
13 + 8x + -6x = 2(x + 5)

Combine like terms: 8x + -6x = 2x
13 + 2x = 2(x + 5)

Reorder the terms:
13 + 2x = 2(5 + x)
13 + 2x = (5 * 2 + x * 2)
13 + 2x = (10 + 2x)

Add '-2x' to each side of the equation.
13 + 2x + -2x = 10 + 2x + -2x

Combine like terms: 2x + -2x = 0
13 + 0 = 10 + 2x + -2x
13 = 10 + 2x + -2x

Combine like terms: 2x + -2x = 0
13 = 10 + 0
13 = 10

Solving
13 = 10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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