8(x+2)-3(x-1)=6(x-2)+2

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Solution for 8(x+2)-3(x-1)=6(x-2)+2 equation: 



8(x+2)-3(x-1)=6(x-2)+2

We move all terms to the left:

8(x+2)-3(x-1)-(6(x-2)+2)=0

We multiply parentheses

8x-3x-(6(x-2)+2)+16+3=0



We calculate terms in parentheses: -(6(x-2)+2), so:

6(x-2)+2

We multiply parentheses

6x-12+2

We add all the numbers together, and all the variables

6x-10

Back to the equation:

-(6x-10)



We add all the numbers together, and all the variables

5x-(6x-10)+19=0

We get rid of parentheses

5x-6x+10+19=0

We add all the numbers together, and all the variables

-1x+29=0

We move all terms containing x to the left, all other terms to the right

-x=-29

x=-29/-1

x=+29

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