8(x+2)-3(x-4=6(x-7)+8

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Solution for 8(x+2)-3(x-4=6(x-7)+8 equation: 



8(x+2)-3(x-4=6(x-7)+8

We move all terms to the left:

8(x+2)-3(x-4-(6(x-7)+8)=0

We multiply parentheses

8x-3(x-4-(6(x-7)+8)+16=0

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