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8(x+2)-3=2x+6(3+x)
We move all terms to the left:
8(x+2)-3-(2x+6(3+x))=0
We add all the numbers together, and all the variables
8(x+2)-(2x+6(x+3))-3=0
We multiply parentheses
8x-(2x+6(x+3))+16-3=0
We calculate terms in parentheses: -(2x+6(x+3)), so:We add all the numbers together, and all the variables
2x+6(x+3)
We multiply parentheses
2x+6x+18
We add all the numbers together, and all the variables
8x+18
Back to the equation:
-(8x+18)
8x-(8x+18)+13=0
We get rid of parentheses
8x-8x-18+13=0
We add all the numbers together, and all the variables
-5!=0
There is no solution for this equation
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