8(x+2)-3=8x+

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Solution for 8(x+2)-3=8x+ equation: 



8(x+2)-3=8x+

We move all terms to the left:

8(x+2)-3-(8x+)=0

We add all the numbers together, and all the variables

8(x+2)-(+8x)-3=0

We multiply parentheses

8x-(+8x)+16-3=0

We get rid of parentheses

8x-8x+16-3=0

We add all the numbers together, and all the variables

13!=0

There is no solution for this equation

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