8(x+2)-6(x+1)=12

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Solution for 8(x+2)-6(x+1)=12 equation: 


Simplifying
8(x + 2) + -6(x + 1) = 12

Reorder the terms:
8(2 + x) + -6(x + 1) = 12
(2 * 8 + x * 8) + -6(x + 1) = 12
(16 + 8x) + -6(x + 1) = 12

Reorder the terms:
16 + 8x + -6(1 + x) = 12
16 + 8x + (1 * -6 + x * -6) = 12
16 + 8x + (-6 + -6x) = 12

Reorder the terms:
16 + -6 + 8x + -6x = 12

Combine like terms: 16 + -6 = 10
10 + 8x + -6x = 12

Combine like terms: 8x + -6x = 2x
10 + 2x = 12

Solving
10 + 2x = 12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 2x = 12 + -10

Combine like terms: 10 + -10 = 0
0 + 2x = 12 + -10
2x = 12 + -10

Combine like terms: 12 + -10 = 2
2x = 2

Divide each side by '2'.
x = 1

Simplifying
x = 1

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