8(x+2)-6=x-1+(2x+1)

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Solution for 8(x+2)-6=x-1+(2x+1) equation: 



8(x+2)-6=x-1+(2x+1)

We move all terms to the left:

8(x+2)-6-(x-1+(2x+1))=0

We multiply parentheses

8x-(x-1+(2x+1))+16-6=0



We calculate terms in parentheses: -(x-1+(2x+1)), so:

x-1+(2x+1)

determiningTheFunctionDomain
x+(2x+1)-1

We get rid of parentheses

x+2x+1-1

We add all the numbers together, and all the variables

3x

Back to the equation:

-(3x)



We add all the numbers together, and all the variables

5x+10=0

We move all terms containing x to the left, all other terms to the right

5x=-10

x=-10/5

x=-2

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