8(x+2)-6=x-1+3(2x+1)

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Solution for 8(x+2)-6=x-1+3(2x+1) equation: 



8(x+2)-6=x-1+3(2x+1)

We move all terms to the left:

8(x+2)-6-(x-1+3(2x+1))=0

We multiply parentheses

8x-(x-1+3(2x+1))+16-6=0



We calculate terms in parentheses: -(x-1+3(2x+1)), so:

x-1+3(2x+1)

determiningTheFunctionDomain
x+3(2x+1)-1

We multiply parentheses

x+6x+3-1

We add all the numbers together, and all the variables

7x+2

Back to the equation:

-(7x+2)



We add all the numbers together, and all the variables

8x-(7x+2)+10=0

We get rid of parentheses

8x-7x-2+10=0

We add all the numbers together, and all the variables

x+8=0

We move all terms containing x to the left, all other terms to the right

x=-8

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