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8(x+2)-6x-1=2x+5(x+1)
We move all terms to the left:
8(x+2)-6x-1-(2x+5(x+1))=0
We add all the numbers together, and all the variables
-6x+8(x+2)-(2x+5(x+1))-1=0
We multiply parentheses
-6x+8x-(2x+5(x+1))+16-1=0
We calculate terms in parentheses: -(2x+5(x+1)), so:We add all the numbers together, and all the variables
2x+5(x+1)
We multiply parentheses
2x+5x+5
We add all the numbers together, and all the variables
7x+5
Back to the equation:
-(7x+5)
2x-(7x+5)+15=0
We get rid of parentheses
2x-7x-5+15=0
We add all the numbers together, and all the variables
-5x+10=0
We move all terms containing x to the left, all other terms to the right
-5x=-10
x=-10/-5
x=+2
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