8(x+2)=4(x+2)+4

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Solution for 8(x+2)=4(x+2)+4 equation: 



8(x+2)=4(x+2)+4

We move all terms to the left:

8(x+2)-(4(x+2)+4)=0

We multiply parentheses

8x-(4(x+2)+4)+16=0



We calculate terms in parentheses: -(4(x+2)+4), so:

4(x+2)+4

We multiply parentheses

4x+8+4

We add all the numbers together, and all the variables

4x+12

Back to the equation:

-(4x+12)



We get rid of parentheses

8x-4x-12+16=0

We add all the numbers together, and all the variables

4x+4=0

We move all terms containing x to the left, all other terms to the right

4x=-4

x=-4/4

x=-1

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