8(x+2)=4(x+5)+2(x-6)

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Solution for 8(x+2)=4(x+5)+2(x-6) equation:



8(x+2)=4(x+5)+2(x-6)
We move all terms to the left:
8(x+2)-(4(x+5)+2(x-6))=0
We multiply parentheses
8x-(4(x+5)+2(x-6))+16=0
We calculate terms in parentheses: -(4(x+5)+2(x-6)), so:
4(x+5)+2(x-6)
We multiply parentheses
4x+2x+20-12
We add all the numbers together, and all the variables
6x+8
Back to the equation:
-(6x+8)
We get rid of parentheses
8x-6x-8+16=0
We add all the numbers together, and all the variables
2x+8=0
We move all terms containing x to the left, all other terms to the right
2x=-8
x=-8/2
x=-4

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