8(x+2)=4(x+5)+2(x-6)

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Solution for 8(x+2)=4(x+5)+2(x-6) equation: 



8(x+2)=4(x+5)+2(x-6)

We move all terms to the left:

8(x+2)-(4(x+5)+2(x-6))=0

We multiply parentheses

8x-(4(x+5)+2(x-6))+16=0



We calculate terms in parentheses: -(4(x+5)+2(x-6)), so:

4(x+5)+2(x-6)

We multiply parentheses

4x+2x+20-12

We add all the numbers together, and all the variables

6x+8

Back to the equation:

-(6x+8)



We get rid of parentheses

8x-6x-8+16=0

We add all the numbers together, and all the variables

2x+8=0

We move all terms containing x to the left, all other terms to the right

2x=-8

x=-8/2

x=-4

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