8(x+2)=4(x-3)

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Solution for 8(x+2)=4(x-3) equation: 



8(x+2)=4(x-3)

We move all terms to the left:

8(x+2)-(4(x-3))=0

We multiply parentheses

8x-(4(x-3))+16=0



We calculate terms in parentheses: -(4(x-3)), so:

4(x-3)

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We get rid of parentheses

8x-4x+12+16=0

We add all the numbers together, and all the variables

4x+28=0

We move all terms containing x to the left, all other terms to the right

4x=-28

x=-28/4

x=-7

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