8(x+2)=6(2x-10)

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Solution for 8(x+2)=6(2x-10) equation: 



8(x+2)=6(2x-10)

We move all terms to the left:

8(x+2)-(6(2x-10))=0

We multiply parentheses

8x-(6(2x-10))+16=0



We calculate terms in parentheses: -(6(2x-10)), so:

6(2x-10)

We multiply parentheses

12x-60

Back to the equation:

-(12x-60)



We get rid of parentheses

8x-12x+60+16=0

We add all the numbers together, and all the variables

-4x+76=0

We move all terms containing x to the left, all other terms to the right

-4x=-76

x=-76/-4

x=+19

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