8(x+3)+2=-8(x-6)-3

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Solution for 8(x+3)+2=-8(x-6)-3 equation: 



8(x+3)+2=-8(x-6)-3

We move all terms to the left:

8(x+3)+2-(-8(x-6)-3)=0

We multiply parentheses

8x-(-8(x-6)-3)+24+2=0



We calculate terms in parentheses: -(-8(x-6)-3), so:

-8(x-6)-3

We multiply parentheses

-8x+48-3

We add all the numbers together, and all the variables

-8x+45

Back to the equation:

-(-8x+45)



We add all the numbers together, and all the variables

8x-(-8x+45)+26=0

We get rid of parentheses

8x+8x-45+26=0

We add all the numbers together, and all the variables

16x-19=0

We move all terms containing x to the left, all other terms to the right

16x=19

x=19/16

x=1+3/16

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