8(x+3)+3=-10(x-8)-7

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Solution for 8(x+3)+3=-10(x-8)-7 equation: 



8(x+3)+3=-10(x-8)-7

We move all terms to the left:

8(x+3)+3-(-10(x-8)-7)=0

We multiply parentheses

8x-(-10(x-8)-7)+24+3=0



We calculate terms in parentheses: -(-10(x-8)-7), so:

-10(x-8)-7

We multiply parentheses

-10x+80-7

We add all the numbers together, and all the variables

-10x+73

Back to the equation:

-(-10x+73)



We add all the numbers together, and all the variables

8x-(-10x+73)+27=0

We get rid of parentheses

8x+10x-73+27=0

We add all the numbers together, and all the variables

18x-46=0

We move all terms containing x to the left, all other terms to the right

18x=46

x=46/18

x=2+5/9

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