8(x+3)-6=2(x+4)

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Solution for 8(x+3)-6=2(x+4) equation: 



8(x+3)-6=2(x+4)

We move all terms to the left:

8(x+3)-6-(2(x+4))=0

We multiply parentheses

8x-(2(x+4))+24-6=0



We calculate terms in parentheses: -(2(x+4)), so:

2(x+4)

We multiply parentheses

2x+8

Back to the equation:

-(2x+8)



We add all the numbers together, and all the variables

8x-(2x+8)+18=0

We get rid of parentheses

8x-2x-8+18=0

We add all the numbers together, and all the variables

6x+10=0

We move all terms containing x to the left, all other terms to the right

6x=-10

x=-10/6

x=-1+2/3

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