8(x+3)=-4(2x-2)

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Solution for 8(x+3)=-4(2x-2) equation: 



8(x+3)=-4(2x-2)

We move all terms to the left:

8(x+3)-(-4(2x-2))=0

We multiply parentheses

8x-(-4(2x-2))+24=0



We calculate terms in parentheses: -(-4(2x-2)), so:

-4(2x-2)

We multiply parentheses

-8x+8

Back to the equation:

-(-8x+8)



We get rid of parentheses

8x+8x-8+24=0

We add all the numbers together, and all the variables

16x+16=0

We move all terms containing x to the left, all other terms to the right

16x=-16

x=-16/16

x=-1

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