8(x+3)=-8x+8(6x-5)

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Solution for 8(x+3)=-8x+8(6x-5) equation: 



8(x+3)=-8x+8(6x-5)

We move all terms to the left:

8(x+3)-(-8x+8(6x-5))=0

We multiply parentheses

8x-(-8x+8(6x-5))+24=0



We calculate terms in parentheses: -(-8x+8(6x-5)), so:

-8x+8(6x-5)

We multiply parentheses

-8x+48x-40

We add all the numbers together, and all the variables

40x-40

Back to the equation:

-(40x-40)



We get rid of parentheses

8x-40x+40+24=0

We add all the numbers together, and all the variables

-32x+64=0

We move all terms containing x to the left, all other terms to the right

-32x=-64

x=-64/-32

x=+2

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