8(x+3)=19x-5+8x-4

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Solution for 8(x+3)=19x-5+8x-4 equation: 



8(x+3)=19x-5+8x-4

We move all terms to the left:

8(x+3)-(19x-5+8x-4)=0

We add all the numbers together, and all the variables

8(x+3)-(27x-9)=0

We multiply parentheses

8x-(27x-9)+24=0

We get rid of parentheses

8x-27x+9+24=0

We add all the numbers together, and all the variables

-19x+33=0

We move all terms containing x to the left, all other terms to the right

-19x=-33

x=-33/-19

x=1+14/19

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