8(x+4)+2(x-3)=6(x+1)

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Solution for 8(x+4)+2(x-3)=6(x+1) equation:



8(x+4)+2(x-3)=6(x+1)
We move all terms to the left:
8(x+4)+2(x-3)-(6(x+1))=0
We multiply parentheses
8x+2x-(6(x+1))+32-6=0
We calculate terms in parentheses: -(6(x+1)), so:
6(x+1)
We multiply parentheses
6x+6
Back to the equation:
-(6x+6)
We add all the numbers together, and all the variables
10x-(6x+6)+26=0
We get rid of parentheses
10x-6x-6+26=0
We add all the numbers together, and all the variables
4x+20=0
We move all terms containing x to the left, all other terms to the right
4x=-20
x=-20/4
x=-5

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