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8(x+4)+6(x-2)+8=3(x-2)-13
We move all terms to the left:
8(x+4)+6(x-2)+8-(3(x-2)-13)=0
We multiply parentheses
8x+6x-(3(x-2)-13)+32-12+8=0
We calculate terms in parentheses: -(3(x-2)-13), so:We add all the numbers together, and all the variables
3(x-2)-13
We multiply parentheses
3x-6-13
We add all the numbers together, and all the variables
3x-19
Back to the equation:
-(3x-19)
14x-(3x-19)+28=0
We get rid of parentheses
14x-3x+19+28=0
We add all the numbers together, and all the variables
11x+47=0
We move all terms containing x to the left, all other terms to the right
11x=-47
x=-47/11
x=-4+3/11
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