8(x+4)-10=3x+20+4x-2

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Solution for 8(x+4)-10=3x+20+4x-2 equation: 



8(x+4)-10=3x+20+4x-2

We move all terms to the left:

8(x+4)-10-(3x+20+4x-2)=0

We add all the numbers together, and all the variables

8(x+4)-(7x+18)-10=0

We multiply parentheses

8x-(7x+18)+32-10=0

We get rid of parentheses

8x-7x-18+32-10=0

We add all the numbers together, and all the variables

x+4=0

We move all terms containing x to the left, all other terms to the right

x=-4

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