8(x+4)=2(19+x)

Solution for 8(x+4)=2(19+x) equation:

8(x+4)=2(19+x)

We move all terms to the left:

8(x+4)-(2(19+x))=0

We add all the numbers together, and all the variables

8(x+4)-(2(x+19))=0

We multiply parentheses

8x-(2(x+19))+32=0


We calculate terms in parentheses: -(2(x+19)), so:

2(x+19)

We multiply parentheses

2x+38

Back to the equation:

-(2x+38)


We get rid of parentheses

8x-2x-38+32=0

We add all the numbers together, and all the variables

6x-6=0

We move all terms containing x to the left, all other terms to the right

6x=6

x=6/6

x=1