8(x+4)=4(2x+1)+28

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Solution for 8(x+4)=4(2x+1)+28 equation: 


Simplifying
8(x + 4) = 4(2x + 1) + 28

Reorder the terms:
8(4 + x) = 4(2x + 1) + 28
(4 * 8 + x * 8) = 4(2x + 1) + 28
(32 + 8x) = 4(2x + 1) + 28

Reorder the terms:
32 + 8x = 4(1 + 2x) + 28
32 + 8x = (1 * 4 + 2x * 4) + 28
32 + 8x = (4 + 8x) + 28

Reorder the terms:
32 + 8x = 4 + 28 + 8x

Combine like terms: 4 + 28 = 32
32 + 8x = 32 + 8x

Add '-32' to each side of the equation.
32 + -32 + 8x = 32 + -32 + 8x

Combine like terms: 32 + -32 = 0
0 + 8x = 32 + -32 + 8x
8x = 32 + -32 + 8x

Combine like terms: 32 + -32 = 0
8x = 0 + 8x
8x = 8x

Add '-8x' to each side of the equation.
8x + -8x = 8x + -8x

Combine like terms: 8x + -8x = 0
0 = 8x + -8x

Combine like terms: 8x + -8x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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