8(x+4)=7(x-4)+x

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Solution for 8(x+4)=7(x-4)+x equation:


Simplifying
8(x + 4) = 7(x + -4) + x

Reorder the terms:
8(4 + x) = 7(x + -4) + x
(4 * 8 + x * 8) = 7(x + -4) + x
(32 + 8x) = 7(x + -4) + x

Reorder the terms:
32 + 8x = 7(-4 + x) + x
32 + 8x = (-4 * 7 + x * 7) + x
32 + 8x = (-28 + 7x) + x

Combine like terms: 7x + x = 8x
32 + 8x = -28 + 8x

Add '-8x' to each side of the equation.
32 + 8x + -8x = -28 + 8x + -8x

Combine like terms: 8x + -8x = 0
32 + 0 = -28 + 8x + -8x
32 = -28 + 8x + -8x

Combine like terms: 8x + -8x = 0
32 = -28 + 0
32 = -28

Solving
32 = -28

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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