8(x+4)=8(2x-1)

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Solution for 8(x+4)=8(2x-1) equation: 



8(x+4)=8(2x-1)

We move all terms to the left:

8(x+4)-(8(2x-1))=0

We multiply parentheses

8x-(8(2x-1))+32=0



We calculate terms in parentheses: -(8(2x-1)), so:

8(2x-1)

We multiply parentheses

16x-8

Back to the equation:

-(16x-8)



We get rid of parentheses

8x-16x+8+32=0

We add all the numbers together, and all the variables

-8x+40=0

We move all terms containing x to the left, all other terms to the right

-8x=-40

x=-40/-8

x=+5

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