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8(x+5)+2=10x-2(x-5)
We move all terms to the left:
8(x+5)+2-(10x-2(x-5))=0
We multiply parentheses
8x-(10x-2(x-5))+40+2=0
We calculate terms in parentheses: -(10x-2(x-5)), so:We add all the numbers together, and all the variables
10x-2(x-5)
We multiply parentheses
10x-2x+10
We add all the numbers together, and all the variables
8x+10
Back to the equation:
-(8x+10)
8x-(8x+10)+42=0
We get rid of parentheses
8x-8x-10+42=0
We add all the numbers together, and all the variables
32!=0
There is no solution for this equation
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