8(x+5)+x=3(x+3)-4

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Solution for 8(x+5)+x=3(x+3)-4 equation: 



8(x+5)+x=3(x+3)-4

We move all terms to the left:

8(x+5)+x-(3(x+3)-4)=0

We add all the numbers together, and all the variables

x+8(x+5)-(3(x+3)-4)=0

We multiply parentheses

x+8x-(3(x+3)-4)+40=0



We calculate terms in parentheses: -(3(x+3)-4), so:

3(x+3)-4

We multiply parentheses

3x+9-4

We add all the numbers together, and all the variables

3x+5

Back to the equation:

-(3x+5)



We add all the numbers together, and all the variables

9x-(3x+5)+40=0

We get rid of parentheses

9x-3x-5+40=0

We add all the numbers together, and all the variables

6x+35=0

We move all terms containing x to the left, all other terms to the right

6x=-35

x=-35/6

x=-5+5/6

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