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8(x+5)+x=3(x+3)-8
We move all terms to the left:
8(x+5)+x-(3(x+3)-8)=0
We add all the numbers together, and all the variables
x+8(x+5)-(3(x+3)-8)=0
We multiply parentheses
x+8x-(3(x+3)-8)+40=0
We calculate terms in parentheses: -(3(x+3)-8), so:We add all the numbers together, and all the variables
3(x+3)-8
We multiply parentheses
3x+9-8
We add all the numbers together, and all the variables
3x+1
Back to the equation:
-(3x+1)
9x-(3x+1)+40=0
We get rid of parentheses
9x-3x-1+40=0
We add all the numbers together, and all the variables
6x+39=0
We move all terms containing x to the left, all other terms to the right
6x=-39
x=-39/6
x=-6+1/2
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