8(x+5)-7(2x+1)=0

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Solution for 8(x+5)-7(2x+1)=0 equation: 



8(x+5)-7(2x+1)=0

We multiply parentheses

8x-14x+40-7=0

We add all the numbers together, and all the variables

-6x+33=0

We move all terms containing x to the left, all other terms to the right

-6x=-33

x=-33/-6

x=5+1/2

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